193 lines
3.5 KiB
C++
193 lines
3.5 KiB
C++
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#include "stdafx.hpp"
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int atoi(const string& s)
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{
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return atoi(s.c_str());
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}
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double atof(const string& s)
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{
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return atof(s.c_str());
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}
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string itoa(int n)
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{
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char buff[32];
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_itoa(n, buff, 10);
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return string(buff);
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}
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//static int _finite( double n ){ // definition: exponent anything but 2047.
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//
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// int e; // 11 bit exponent
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// const int eMax = 2047; // 0x7ff, all bits = 1
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//
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// int *pn = (int *) &n;
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//
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// e = *++pn; // Intel order!
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// e = ( e >> 20 ) & eMax;
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//
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// return e != eMax;
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//}
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//
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//static int _isnan( double n ){ // definition: exponent 2047, nonzero fraction.
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//
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// int e; // 11 bit exponent
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// const int eMax = 2047; // 0x7ff, all bits = 1
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//
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// int *pn = (int *) &n;
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//
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// e = *++pn; // Intel order!
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// e = ( e >> 20 ) & eMax;
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//
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// if ( e != 2047 ) return 0; // almost always return here
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//
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// int fHi, fLo; // 52 bit fraction
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//
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// fHi = ( *pn ) & 0xfffff; // first 20 bits
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// fLo = *--pn; // last 32 bits
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//
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// return ( fHi | fLo ) != 0; // returns 0,1 not just 0,nonzero
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//}
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/////////////
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//By FLOYD!//
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/////////////
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string ftoa(float n)
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{
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static const int digits = 6;
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int eNeg = -4, ePos = 8; // limits for e notation.
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char buffer[50]; // from MSDN example, 25 would probably suffice
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string t;
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int dec, sign;
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if (_finite(n)) {
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// if ( digits < 1 ) digits = 1; // less than one digit is nonsense
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// if ( digits > 8 ) digits = 8; // practical maximum for float
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t = _ecvt(n, digits, &dec, &sign);
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if (dec <= eNeg + 1 || dec > ePos) {
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_gcvt(n, digits, buffer);
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t = buffer;
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return t;
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}
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// Here is the tricky case. We want a nicely formatted
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// number with no e-notation or multiple trailing zeroes.
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if (dec <= 0) {
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t = "0." + string(-dec, '0') + t;
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dec = 1; // new location for decimal point
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} else if (dec < digits) {
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t = t.substr(0, dec) + "." + t.substr(dec);
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} else {
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t = t + string(dec - digits, '0') + ".0";
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dec += dec - digits;
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}
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// Finally, trim off excess zeroes.
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int dp1 = dec + 1, p = t.length();
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while (--p > dp1 && t[p] == '0')
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;
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t = string(t, 0, ++p);
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return sign ? "-" + t : t;
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} // end of finite case
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if (_isnan(n))
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return "NaN";
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if (n > 0.0)
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return "Infinity";
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if (n < 0.0)
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return "-Infinity";
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abort();
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}
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/*
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string ftoa( float n ){
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static const float min=.000001f,max=9999999.0f;
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int i=*(int*)&n;
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int e=(i>>23)&0xff;
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int f=i&0x007fffff;
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if( e==0xff && f ) return "NAN";
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string t;
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int s=(i>>31)&0x01;
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if( e==0xff ){
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t="INFINITY";
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}else if( !e && !f ){
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t="0.000000";
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}else if( n>=min && n<=max ){
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int dec,sgn;
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t=_fcvt( fabs(n),6,&dec,&sgn );
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if( dec<=0 ){
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t="0."+string( -dec,'0' )+t;
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}else if( dec<t.size() ){
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t=t.substr( 0,dec )+"."+t.substr( dec );
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}else{
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t=t+string( '0',dec-t.size() )+".000000";
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}
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}else{
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char buff[32];
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_gcvt( fabs(n),7,buff );
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t=buff;
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}
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return s ? "-"+t : t;
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}
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*/
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string tolower(const string& s)
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{
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string t = s;
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for (int k = 0; k < t.size(); ++k)
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t[k] = tolower(t[k]);
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return t;
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}
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string toupper(const string& s)
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{
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string t = s;
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for (int k = 0; k < t.size(); ++k)
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t[k] = toupper(t[k]);
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return t;
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}
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string fullfilename(const string& t)
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{
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char buff[MAX_PATH + 1], *p;
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GetFullPathName(t.c_str(), MAX_PATH, buff, &p);
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return string(buff);
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}
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string filenamepath(const string& t)
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{
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char buff[MAX_PATH + 1], *p;
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GetFullPathName(t.c_str(), MAX_PATH, buff, &p);
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if (!p)
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return "";
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*p = 0;
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return string(buff);
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}
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string filenamefile(const string& t)
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{
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char buff[MAX_PATH + 1], *p;
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GetFullPathName(t.c_str(), MAX_PATH, buff, &p);
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if (!p)
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return "";
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return string(p);
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}
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